讨论测度链上二阶边值问题,xΔΔ+k(t)f(t,x(σ(t)))=0,t∈[t1,t2],αx(t1)-βxΔ(t1)=0,γx(σ(t2))+δxΔ(σ(t2))=0正解的存在性,[t1,t2]T,T是测度链,利用Leggett-Williams不动点定理,可得该问题至少存在3个正解.
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